number of nodal planes in antibonding pi 2 px orbital
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Answered by
36
The anti-bonding sigma p orbitals have three nodal planes. The sigma p bonding orbital is the lowest energy orbital which means it will have zero nodes. Then there is the pi bonding orbitals (1 node), the pi anti-bonding orbitals (2 nodes) and finally the anti-bonding sigma p orbital which has three nodes.
This is an MO diagram of HX (X being a halogen). As you go up in energy the number of nodes increases. Just remember that the p orbital has a node in the center so include that when you are counting the number of nodes.
Answered by
13
Hii friend ,
The answer is probably 1.
because three are the nodal 2p xy ,2p yz, and 2p xz.
and each of them are represent the axis other than the the letters.
I mean for 2p x orbital the nodal plane is "YZ" plane.
Hope this helps you a little!!!!
The answer is probably 1.
because three are the nodal 2p xy ,2p yz, and 2p xz.
and each of them are represent the axis other than the the letters.
I mean for 2p x orbital the nodal plane is "YZ" plane.
Hope this helps you a little!!!!
Rock42:
thanks for answering but the answer is 2 p* 2px has two nodal planes
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