Question

Ok in an ap,if a=10,d=5and n=100,then find the value of a100 and also find the 50th term from the end

Answer 1

since,a100=a+(n-1)d
a100=10+(99)5
a100=450
now there are 100 terms totally now formula is
$(n - r + 1) {th}^{term}$
r=50 now,you get 51th term i.e.50th term form last is 51th term form starting
so a51=10+(50)5
a51=260
so 50th term from last is 260

Answer 2

Answer:

505,260

Step-by-step explanation:

since,a100=a+(n-1)d

a100=10+(99)5

a100=505

now there are 100 terms totally now formula is

(n - r + 1) {th}^{term}(n−r+1)th

term

r=50 now,you get 51th term i.e.50th term form last is 51th term form starting

so a51=10+(50)5

a51=260

so 50th term from last is 260

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