Question

on a common hypotenuse AB,two right triangles ACB & ADB are situated on opposite sides . prove that angle BAC = angle BDC

Answer 1

Given ,
ACB and ADB are two right triangles
To Prove,
<BAC=<BDC
<Proof,
<C + <D = 90° + 90°
               = 180°
Therefore ADBC is a Cyclic Quadrilateral
<BAC​ and <BDC​ are made by the same arc BC
Therefore,
<BAC=<BDC​
Hence Proved
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Answer 2

Answer:

hello

Step-by-step explanation:

Given ,

ACB and ADB are two right triangles

To Prove,

<BAC=<BDC

<Proof,

<C + <D = 90° + 90°

              = 180°

Therefore ADBC is a Cyclic Quadrilateral

<BAC​ and <BDC​ are made by the same arc BC

Therefore,

<BAC=<BDC​

Hence Proved