Question

one gram mole of gas at NTP occupies 22.4 L this fact was derived from a)law of cnstnt composition b)avagadros hypothesis c)gay lussac's law of combining volume d)daltons atomic theory

Answer 1

I think answer is (b)
because according to avogadro law :- under similar conditions of temperature and pressure equal volume of gases contains equal no of molecules
i.e. pv=nRT
v=nRT/p
we put n=1 R, T and P value at NTP
then we find v=22.4L

Answer 2

Answer:  b) avogadros hypothesis

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas at NTP = 1 atm

V= Volume of the gas = ?

T= Temperature of the gas = 0°C = 273 K    $(0^0C=273k)$

R= Gas constant = 0.0821 atmL/K mol

n=  moles of gas= ?1 gram mole = 1 mole

$V=\frac{nRT}{P}=\frac{1\times 0.0821\times 273}{1}=22.4moles$

Thus the given fact was derived from Avogadros hypothesis.