Question

one of the 2 numbers exceeds the other by 9. Four times the smaller added to Five times the larger gives 108.Find the numbers

Answer 1

let the smaller number = x

then the larger number exceed the smaller number by 9 = x + 9

Given that four times ,
the smaller added to five times the larger gives 108

4x + 5 ( x + 9 ) = 108

4x + 5x + 45 = 108

9x + 45 = 108

9x = 108 - 45

9x = 63

x = 63 / 9

x = 7


then the larger number :

= 9 + 7 = 16
therefore the numbers are 7 and 16

....................@...................