Question

one of the two digits number is three times the other digit.If you interchange the digits of this two digit numbers and add the resulting number, you get 88.What is the original number?

Answer 1

Answer is 26 or 62

You can check

Answer 2

let , that one digit be x and other y .

from first condition

1ox+3y

from second condition

3y(10) +x

so add both numbes

x+10x+30y+3y=88

11x+33y=88

Divinding by 11 to both sides

X+3y=8........1

SO there is no another equation

Hence take value of x

X=1

Then 1+3y=8

3y=8-1

3y=7

Y=7/3.(but it is not a rational number)

So put x=2

2+3y=8

3y=8-2

3y=6

Y=6/3

Y=2

So the original number is 10x+3(y)

10*2+3*2

20+6

26

Hope it help you