One of the two digits of a two-digit number is two times the other digit. On reversing the digits, the new number obtained is 36 less than the original number. What is the original number?
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Let the digit in ones place be x
digit in tens place be y
Therefore the number is 10y+x
Reversed number = 10x+y
By the given conditions,
y = 2x
10x+y = 10y+x-36
9x-9y = -36
x-y = -4
x-2x = -4
-x = -4
x = 4
y = 2*4
y = 8
Therefore the number is 80+4 = 84
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