Question

One third of the sum of the sides of rectangle is 60cm. Quarter of their difference is 28cm.Find the dimensions of the rectangle by Crammer's rule​

Answer 1

Answer:Let the two angles be 'x' and 'y'.

So, according to the question,

One third of the sum of two angles :- 1/3(x+y) = 60  

x/3 + y/3 = 60    ......(1)

Quarter of their difference :- 1/4(x-y) = 28  

x/4 - y/4 = 28...........(2)

Multiplying the equation (1) by 3 and equation (2) by 4, we get

x + y =180  .......(3)   x - y = 112  ......(4)

Subtracting (4) from (3),

x + y = 180

x - y = 112

-   +     -

_________

   2y = 68

_________

2y = 68

y = 34

Putting the value of y = 34 in the equation (3)

x + y = 180

x + 34 = 180

x = 180 - 34

x = 146

The two angles are 146° and 34°.

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