Question

♡only geniues♡

let ABC be a right Triangle in which AB equal to 6 cm BC = 8 cm and angle B = 90° BD is the perpendicular from B on AC the circle through B,C,D is drawn construct the tangents from a to this circle ?

Note:-Class 10 maths constriction.
Don't copy ❌
steps of construction must.


#Dramaqueen⭐​

Answer 1

▶️STEPS OF CONSTRUCTION;

⏩ Draw a triangle ABC
with AB=6cm,BC=8cm and Angle B=90°
⏩ Join AO and bisect it at M
⏩ Take M as centre and MA as the radius
draw a circle
it intersect the given circle at the points By and E
⏩ Join AB and AE
⏩▶️Here AB and AE are the required tangents

Answer 2

Step-by-step explanation:

1. Draw a line segment BC = 8 cm.

2. Make a right angle at the point B i.e., ∠CBX = 90°

3. Draw a are of radius 6 cm as centre B which intersect BX at the point A.

4. Join AC  so, ABC is required right angle triangle.

5. Draw a arc taking centre B which intersect AC at the point K and L respectively taking K and L centre draw two arcs of same radius which intersect at the point M.

6. Join BM so, ∠BDC = 90°

7. Draw perpendicular bisector of BC.

8. Draw a circle taking radius equal to OB and centre O which passes through B, D and C.

9. Draw a arc taking centre A and radius equal to AB intersect the circle at point P so, AP is the tangents