Question

only maths experts required urgently

The angle of elevation of the top of the tower from a point on the ground , which is 15 metres away from the foot of the tower is 60°
Height of the tower is ????

Answer 1

The angle of elevation of the top of a tower from a point on the ground, which is 15 m away from the foot of the tower is 60°. The height of the tower is ?

Refer the attachment for figure.

Solution :

In the given figure, AB is the height of the tower.

BC = 15 m.

Angle of the elevation = theta = /_BCA = 60°

From figure,

tanθ= BC/ AB ...(1)

tan 60° = √3 ... (2)

From (1) and (2) ,

AB/BC = √3

Therefore,

AB = BC × √3

AB = 15 √3 or 26 m.

Considering √3 = 1.73 ( approx. )

Thus, Height of the tower is 15 √3 metres or 26 metres ( approx. ).

Answer 2

The height of the tower is AC is 15*1.73