Question

(p+4)
${(p + 4)}^{2}$
​

Answer 1

• ${\bold{(p + 4)}}^{\bold{2}}$

${ }$

$\:\:\:\:\:\:\::\:\Longrightarrow{\sf{p}^{2}}\:{\sf{+\:4}^{2}}\:{\sf{+\:2\:.\:p\:.\:4}}$

${ }$

$\:\:\:\:\:\:\::\:\Longrightarrow{\sf{\bold{By\:Using\:=\:a}^{2}}\:{\sf{\bold{+\:b}^{2}}}\:{\sf{\bold{+\:2\:ab}}}}$

${ }$

$\:\:\:\:\:\:\::\:\Longrightarrow{\sf{p}^{2}}\:{\sf{+\:16}}\:{\sf{+\:8p}}$

${ }$

$\:\:\:\:\:\:\::\:\Longrightarrow{\sf{p}^{2}}\:{\sf{+\:8p}}\:{\sf{+\:16\:=\:0}}$

${ }$

$\:\:\:\:\:\:\::\:\Longrightarrow{\sf{p}^{2}}\:{\sf{+\:(4\:+\:4)\:p\:+\:16\:=\:0}}$

${ }$

$\:\:\:\:\:\:\::\:\Longrightarrow{\sf{p}^{2}}\:{\sf{+\:4p\:+\:4p\:+\:16\:=\:0}}$

${ }$

$\:\:\:\:\:\:\::\:\Longrightarrow{\sf{p\:(p\:+\:4)\:+\:4\:(p\:+\:4)\:=\:0}}$

${ }$

$\:\:\:\:\:\:\::\:\Longrightarrow{\sf{p\:+\:4\:=\:0\:;\:p\:+\:4\:=\:0}}$

${ }$

$\:\:\:\:\:\:\::\:\Longrightarrow{\underline{\boxed{\bold{\sf{p\:=\:-4\:;\:p\:=\:-4}}}}}\:★$

Answer 2

$\huge \sf \red{αƞៜwεʀ}$

• $\huge \bold {(p + {4)}}^{2}$

=> pᒾ + 4ᒾ + 2. p. 4

$:\mapsto\bold \pink{By Using = aᒾ + bᒾ + 2ab}$

$\: \: \: \: \: \: \: \: : \implies \sf \green {{p}^{2} + 8p + 16 = 0} \\ \\ \: \: \: \: \: \: \: \: : \implies \sf \green{ {p}^{2} + 8p + 16 = 0 } \\ \\ \: \: \: \: \: \: \: \: : \implies \sf \green{p(p + 4) + 4(p + 4) = 0}$

$\: \: \: \: \: \: \: \: : \implies \sf \green{p + 4 = 0; p + 4 = 0}$

$\: \: \: \: \: \: \: \: : \implies \sf \green{p = - 4; p = - 4}$

$\sf \blue{@CherryQueen02}$