Question

physics questions ???????

Answer 1

The circuit shown in the figure could also be drawn as shown in the attachment .



Now,
Simplify the resistance in the series, and you'll end up with resistance of 13Ω and 7 Ω in parallel.

So the equivalent resistance between A and B will be
$\frac{1}{r} = \frac{1}{13} + \frac{1}{7} \\ \frac{1}{r} = \frac{20}{91} \\ r = \frac{91}{20} = 4.55$


So,
Option A is the correct one.

Answer 2

Answer:

c

Explanation:

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