Question

please answer me these questions if x=2-root 5, find the value of x +1upon x, x - 1 upon x​

Answer 1

Answer:

just put the value of x in equations

x + 1= ( 2 -√ 5 ) + 1

=> 2 -√5 + 1

=3 -√5

in second case

x - 1= (2 -√ 5) -1

=> 2 -√5 - 1

=> 1 -√ 5

Answer 2

Answer:

x=2-√5

first we will put the value x that is

x+1/x

2-√5+1÷2-√5

multiple 2+√5 because there can't be √ in denominator

3-√5÷2-√5×2+√5÷2+√5

putting identity a square+ b square=(a+b) (a-b)

3-√5 ×(2+√5)÷2 square- √5 square