please answer this question fast 5 th one
Attachments:
Answers
Answered by
0
Angle OAB = 20 Angle AED = 120
Also BC= OA
Thus Angle OAB = Angle ABC [Alternate angles]
Thus angle ABC= 20 deg
Now
In triangle ACB
Angle BAC + Angle ABC + Angle ACB = 180
angle BAC + 90 + 20 = 180
Angle BAC = 180 - 110
= 70 deg
In quad ACEF
Angle EFC + 90 + 70 + 120 = 360
Angle EFC = 360 - 280
= 80
Thus CFD = 180 - 80 = 100 deg
Also BC= OA
Thus Angle OAB = Angle ABC [Alternate angles]
Thus angle ABC= 20 deg
Now
In triangle ACB
Angle BAC + Angle ABC + Angle ACB = 180
angle BAC + 90 + 20 = 180
Angle BAC = 180 - 110
= 70 deg
In quad ACEF
Angle EFC + 90 + 70 + 120 = 360
Angle EFC = 360 - 280
= 80
Thus CFD = 180 - 80 = 100 deg
Similar questions
Chemistry,
8 months ago
English,
8 months ago
Political Science,
8 months ago
Social Sciences,
1 year ago
Math,
1 year ago