Question

Please seriously give answer!!!!

Answer 1

Answer:

14 m

Step-by-step explanation:

(i)

Given, outer circumference (r₁) = 308 m.

⇒ 2πr₁ = 308

⇒ 2 * (22/7) * r₁ = 308

⇒ (44/7) * r₁ = 308

⇒ r₁ = 2156/44

⇒ r₁ = 49 m

(ii)

Given,Inner circumference (r₂) = 220 m.

⇒ 2πr₂ = 220

⇒ 2 * (22/7) * r₂ = 220

⇒ (44/7) * r₂ = 220

⇒ 44r₂ = 1540

⇒ r₂ = 35 m.

Therefore, width of the track = (49 - 35)

⇒ 14 m.

Hope it helps!