Question

please solve it fast
urgent
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Answer 1

Step-by-step explanation:

1) x^2-3x-10= 0. [ax^2+bx+c=0]

(-10)*1= -10

(-5)*2= -10

(-5)+2= -3

=> x^2-5x+2x-10=0

=> x(x-5)+2(x-5)=0

=> (x+2)(x-5)=0

x= -2 or. x=5

2) 2x^2+x-6=0. [ax^2+bx+c=0]

2*(-6)= -12

4*(+3)= -12

4+(-3)= 1

=> 2x^2+4x-3x-6=0

=> 2x(x+2)-3(x+2)=0

=> (2x-3)(x+2)=0

x=3/2. or. x= -2

this is your answer

Mark as brainlist

Answer 2

Answer:

x^2 +2x-5x-10=0

(x-5)(x+2)=0

×=5,-2