Math, asked by chagahak1, 1 year ago

please solve this problem

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Answers

Answered by Satviksaketh
0
(5x-1)
(5x - 1) {}^{2}  - 36y {}^{2}  \\(5x - 1 - 6y) \times (5x - 1 + 6y) \\
Answered by dbhattacharyya
0
25x^2-10x+1-36y^2
={(5x)^2}-(2×5x×1)+{(1)^2}-{(6y)^2}
=(5x-1)^2-(6y)^2[(a-b)^2=a^2-2ab+b^2]
=(5x-1+6y)(5x-1-6y)[a^2-b^2=(a+b)(a-b)]
Ans: (5x-1+6y)(5x-1-6y)
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