pls ans this too......
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tan75°-cot75°
=(sin^75° - cos^75°) / (sin75° . cos75°)
= -2cos150°/sin150
= 2cot150°
=-2(-tan60°)
=2√3
so, tan75°-cot75°= 2√3
Answer Is Option (A)
Hope My Answer Helped
(:
★→Answer←★
tan75°-cot75°
=(sin^75° - cos^75°) / (sin75° . cos75°)
= -2cos150°/sin150
= 2cot150°
=-2(-tan60°)
=2√3
so, tan75°-cot75°= 2√3
Answer Is Option (A)
Hope My Answer Helped
(:
akshita113:
2nd line jha per
sin or cos aagye
vo kaise aaw
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