pls answer my question
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Game Cds purchased by Gautam =x²+8x-20
By splitting the middle term method :
x²+10x-2x-20=0
x(x+10)-2(x+10)=0
(x-2)(x+10)=0
Now x can be equal to 2 or -10 .
since x is the number of cds, hence it cant be negative.
Therefore x(cds purchased by Gautam)=2
Now,
the number of cds purchased by sanju =(x+4)²
using formula (a+b)²= a²+ b² +2a.b
(x+4)²=x²+16+8x
x²+16+8x
Equating to 0,to solve for x
x²+8x+16=0 (write in standard form)
by splitting the mjddle term (one can use quadratic formula too.)
x²+4x+4x+16=0
x(x+4) +4(x+4)=0
(x+4)(x+4)=0
x=-4,-4
since x are cds purchased by sanju ,it cant be negative.
hence cds purchased by sanju = 4
therefore ,
a) Sanju purchases more cds than gautam by 4-2=2
b) Hope you do this urself. ;)
By splitting the middle term method :
x²+10x-2x-20=0
x(x+10)-2(x+10)=0
(x-2)(x+10)=0
Now x can be equal to 2 or -10 .
since x is the number of cds, hence it cant be negative.
Therefore x(cds purchased by Gautam)=2
Now,
the number of cds purchased by sanju =(x+4)²
using formula (a+b)²= a²+ b² +2a.b
(x+4)²=x²+16+8x
x²+16+8x
Equating to 0,to solve for x
x²+8x+16=0 (write in standard form)
by splitting the mjddle term (one can use quadratic formula too.)
x²+4x+4x+16=0
x(x+4) +4(x+4)=0
(x+4)(x+4)=0
x=-4,-4
since x are cds purchased by sanju ,it cant be negative.
hence cds purchased by sanju = 4
therefore ,
a) Sanju purchases more cds than gautam by 4-2=2
b) Hope you do this urself. ;)
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