Math, asked by harjotsinghbhinder13, 11 months ago

pls help me
????plz help

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Answered by Anonymous
0
cosec22 = cosec(90-68) = sec 68

tan43 = tan( 90-47) = cot47

tan12 = tan(90-78) = cot 78

SO

3 cos68 sec68 - 1/2. cot 47 tan 47 cot78 tan60 tan78

AS sec 68 = 1/cos68
cot 47 = 1/tan47

tan78 = 1/cot 78

SO
IT BECOMES

3 - 1/2 .√3

(6-√3)/2
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