Math, asked by rosy1746, 1 year ago

pls help me solve this

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Answers

Answered by famitha
0
cos a = 3/5
cos

2

A=

(

3

5

)

2

=

9

25

Since 

sin

2

A+

cos

2

A=1, so we have

    

sin

2

A=1−

cos

2

A

             =1−

(

3

5

)

2

             =1−

9

25

             =

25−9

25

             =

16

25

So the given expression beocmes

      9 

cot

2

A−1=9

cos

2

A

sin

2

A

−1     

 (since cotA=

cosA

sinA

)

                        =9

9

25

16

25

−1

                        =9×

9

16

−1

                        =

81

16

−1

                        =

81−16

16

                        =

65

16

     

Answered by famitha
0
cos a = 3/5
cos

2

A=

(

3

5

)

2

=

9

25

Since 

sin

2

A+

cos

2

A=1, so we have

    

sin

2

A=1−

cos

2

A

             =1−

(

3

5

)

2

             =1−

9

25

             =

25−9

25

             =

16

25

So the given expression beocmes

      9 

cot

2

A−1=9

cos

2

A

sin

2

A

−1     

 (since cotA=

cosA

sinA

)

                        =9

9

25

16

25

−1

                        =9×

9

16

−1

                        =

81

16

−1

                        =

81−16

16

                        =

65

16

     


rosy1746: seriously i didn't understand anything
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