Question

pls pls give me ans faster a stone tied to the end of a string of 1m long is Whirled in horizontal circle with a constant speed.lf the stone make 22 revolution in 44 sc,what is magnitude and direction of acceleration of the stone? (ans is π^2)​

Answer 1

Answer:

π² m/s²

Explanation:

frequency = 22 rev / 44 s

= 0.5 Hz

Centripetal Acceleration = rω²

= r(2πf)²

= 1 m × (2 × π × 0.5 Hz)²

= 1 m × (π Hz)²

= 1 m × π² Hz²

= π² m/s²