Question

pls solve 32 nd and 33rd​

Answer 1

⭐Solution '⭐

✔Given here

√[ (secA -1) /(secA+1)] + [ √(secA+1)/(secA-1)] = 2CosecA .

✅Take here LHS.

= √[ (secA -1) /(secA+1)] + [ √(secA+1)/(secA-1)]

= [√(secA-1)√(secA-1)+√(secA+1)√(secA+1)]/√(Sec²A-1)

= (secA-1+SecA+1)/TanA

= 2SecA/TanA

= 2 (1/CosA )× (CosA/SinA)

= 2/SinA

= 2CosecA.

= RHS.

✨Thats Proved ✨

✨Hopes its help's u

✔Marks Brainliest.