Question

plz answer this question

Answer 1

by law of conservation of momentum m1v1=m2v2 ...... eq1

m1=0.02kg , v1=150m/s  , m2=2kg (if u meant to as 2)

we know from eq 1 that v2=m1v1/m2=0.02*150/2

solve to get the recoil velocity of the pistol

ans is ...........  1.5m/s