Question

Plz answer this question it's really urgent. Plz help me out guys. ​

Answer 1

ANSWER

Let the number of males in previous year be x and number of female be y.

Now,

by first condition x+y= 50000.......(1)

Male population increased by 5%

Therefore number of males,

$\\ \frac{105}{100} x$

Female population increased by 3%

Therefore number of females,

$\\ \frac{103}{100} y$

From second condition,

$\\ \frac{105}{100}x + \frac{103}{100} y = 52020 \\ \\ 105x + 103y = 5202000......(2)$

Multiplying equation (1) by 103,

105x + 103y =5150000......(3)

Subtracting equation (3) from (2)

2x= 5202000-510000

2x= 52000.

Number of males

$\\ x = \frac{52000}{2} \\ \\ x = 26000$

Number of females,

Put the above value of x in equation (1)

x + y = 50000.....(1)

26000+y=50000

y= 50000-26000

y= 24000.

Number of males,

x= 26000.

Number of females,

y= 24000.

Answer 2

Answer

x+y= 50000

increased of males = 5%

$\begin{lgathered}\\ \frac{105}{100} x\end{lgathered}$

(100(105 x)

increased of demals=3%

$\begin{lgathered}\\ \frac{103}{100} y\end{lgathered}$

(100(103= y)

$\begin{lgathered}\\\frac{105}{100}x + \frac{103}{100}y=52020$

105x + 103y = 5202000

(100(105 x+ 100(103)

y=52020

105x+103y=5202000

Multiplying equation (1) by 103,

105x + 103y =5150000......(3)

Subtracting equation (3) from (2)

2x= 5202000-510000

2x= 52000.

Number of males

$\begin{lgathered}\\ x = \frac{52000}{2} \\ \\ x = 26000\end{lgathered}$

x= 252000

x=26000

Number of females,

x + y = 50000

26000+y=50000

y= 50000-26000

y= 24000.

Number of males,

x= 26000.

Number of females,

y= 24000.

Answer=5202000