Question

plz solve the problem plz help me

Answer 1

${a}^{2 - x} . {b}^{5x} = {a}^{x + 3} . {b}^{3x} \\ {b}^{5x - 3x} = {a}^{x + 3 - 2 + x} \\ {b}^{2x} = {a}^{x + 1}$

taking log on both sides,

$2x log(b) = (x + 1) log(a) \\ 2x log(b) = 2x log(a) + log(a) \\ 2x log(b) -2 x log(a) = log(a) \\ x(2 log(b) -2 log(a) ) = log(a) \\2 x log( \frac{ {b}}{a} ) = log(a) \\ \\ \bold{x log( \frac{b}{a} ) = log(a) }$

please follow me