Question

Plz solve this question

Answer 1

h+2=velocity ^2÷2*g
hope this helps you

Answer 2

Let the distance of the top of the window from roof = S meter

let time taken by the stone to cover S = t seconds

initial velocity = 0

So S = ut + 1/2 at^2

=> S = 0 + 1/2 × 10 × t^2

=> S = 5t^2


Given that it takes 0.1 second to cover the 2m high window. So it will take (t + 0.1)Seconds to cover (S+2) meters.

So (S+2) = 0×(t+0.1) + 1/2 × 10 × (t+0.1)^2

=> S + 2 = 5(t+0.1)^2

=> S + 2 = 5(t^2 + 0.01 + 0.2t)

=> 5t^2 + 2 = 5t^2 + 0.05 + t

=> 5t^2 - 5t^2 + 2 - 0.05 = t

=> t = 1.95 s


Now S = 5t^2 = 5 × 1.95^2 = 19.01 m

Hence, roof is 19.01m above the top of window.