plzz ans.....Thnk you....Logarithms
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Hello there !!!!!
x=1+log2-log5 y=2log3 z=loga-log5
x+y=2z
(1-log5+log2)+2log3=2(loga-log5)
We can write 1=log10
So,
(log10-log5+log2)+2log3=2(loga-log5)
(log10/5+log2)+2log3=2(loga/5)
log2+log2+2log3=2(loga/5)
2log2+2log3=2(loga/5)
2(log2+log3)=2(loga/5)
We know tat loga+logb=logab
So,
2(log2+log3)=2(loga/5)
log6=loga/5
6=a/5
a=6*5=30
Hope this helped you ...........
x=1+log2-log5 y=2log3 z=loga-log5
x+y=2z
(1-log5+log2)+2log3=2(loga-log5)
We can write 1=log10
So,
(log10-log5+log2)+2log3=2(loga-log5)
(log10/5+log2)+2log3=2(loga/5)
log2+log2+2log3=2(loga/5)
2log2+2log3=2(loga/5)
2(log2+log3)=2(loga/5)
We know tat loga+logb=logab
So,
2(log2+log3)=2(loga/5)
log6=loga/5
6=a/5
a=6*5=30
Hope this helped you ...........
sanj2:
thnk u .....u helped me alot
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