Question

plzz answerand get points

Answer 1

 SOLUTION :- > 

in the figure which i made for u bro u can see that B is the position of boy and G  is the position where girl is standing  now brother 

in triangle PQB :- 
PQ/PB = sin 30 °  as sinx = perpendicular / hypotaneous 

and here PB = 100 
PQ/100 = sin30 
PQ= 100/2= 50 
so  we got PQ = 50 dide ! 
 now dude PS= PQ - SQ = PQ- GR = > 50-20= 30 
now we got PS which equals to = 30 m 

now dude in triangle PSG :- 

PS/PG = sin 45 °
and here PS = 30 m 
30/PG= 1/√2
we got PG = > 30√2 m 
hence we get that  the bird is flying at a distance of 30√2 m 

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hope this helps you my dude ! 

Answer 2

in triangle PQB :-

PQ/PB = sin 30 ° as sinx = perpendicular / hypotaneous

and here PB = 100

PQ/100 = sin30

PQ= 100/2= 50

so we got PQ = 50

After this??