Question

plzz help..........​

Answer 1

Given :-

A current of 0 . 1 A passes through a coil.

Resistance of coil is 50Ω .

Time of flow is 2 min .

To Find :-

The heat produced in Joules .

Formula Used :-

$\large\boxed{\red{\bf\green{\dag}\:Heat\:=\:I^2Rt}}$

$\color{cyan}\bf \qquad\qquad Derivation\:of\:Formula:-$

$\tt According\:to\:Joules\:Law\:of\:heating:-$

$\sf\purple{\qquad\orange{\mapsto} Heat \propto (Current)^2}$

$\sf\purple{\qquad\orange{\mapsto} Heat \propto Time}$

$\sf\purple{\qquad\orange{\mapsto} Heat \propto Resistance}$

$\tt From \: above\:three\: equations\::-$

$\underline{\boxed{\red{\tt{\longmapsto Heat=I^2Rt}}}}$

Calculation :-

Here , as per data in Question ,

$\sf Time = 2min = 2\times60s=120s$

$\sf Resistance = 50\Omega$

$\sf Current = 0.1A$

$\tt\pink{ Now \:put\: respective \:values\: in \:above\: formula:}$

$\tt:\implies Heat = I^2Rt$

$\tt:\implies Heat = (0.1 A)^2\times 50\Omega \times 120s$

$\tt:\implies Heat = \bigg\lgroup \dfrac{1}{1\cancel0\cancel0}\times 5\cancel0\Omega\times12\cancel0s \bigg\rgroup$

$\tt:\implies Heat = 5\times 12 Joules$

$\underline{\boxed{\red{\tt{\longmapsto Heat=60 Joules }}}}$

$\boxed{\green{\bf \pink{\dag}\:Hence\:the\:heat\;developed\:is\:60\:Joules.}}$

Answer 2

Answer:

The heat developed is 60 joules..

Hope it helps...