plzz solve question number 17 of airthemetic progression
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answer is 92
AP is 8,14,20.............
AP is 8,14,20.............
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hey dear your ans is here ⬇⬇
since we have given that the sum of nth terms of an ap = 3n^2 + 5n
then , sum of 1 term = 3 ×(1)^2 + 5 ×1 = 8.
and sum of 2 terms = 3 × (2)^2 + 5× 2 = 22.
and the sum of 3 terms = 3 × (3)^2 + 5×3 = 42.
now here we will find. ..a1 = s1 - s0
= 8- 0 = 8
and , a2 = s2 - s1 = 22 - 8 = 14
a3 = s3 - s2 = 42 - 22 = 20 .
now here .. a 1 = 8 and common difference = 6 .
so ap = 8, 14 , 20, 26 , 32............
and hence the 15term = a + 14 d
= 8 + 14× 6
= 8+ 84 = 92.
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since we have given that the sum of nth terms of an ap = 3n^2 + 5n
then , sum of 1 term = 3 ×(1)^2 + 5 ×1 = 8.
and sum of 2 terms = 3 × (2)^2 + 5× 2 = 22.
and the sum of 3 terms = 3 × (3)^2 + 5×3 = 42.
now here we will find. ..a1 = s1 - s0
= 8- 0 = 8
and , a2 = s2 - s1 = 22 - 8 = 14
a3 = s3 - s2 = 42 - 22 = 20 .
now here .. a 1 = 8 and common difference = 6 .
so ap = 8, 14 , 20, 26 , 32............
and hence the 15term = a + 14 d
= 8 + 14× 6
= 8+ 84 = 92.
hey dude I hope this would helpful for u ☺
✔ so please mark it as brainliest ans.
and follow me☺
{♡♡♡ THANK YOU ♡♡♡} .
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