plzzz ans....Logarithms....Thnk you
Attachments:
Answers
Answered by
2
Hey there !!!!
log(m+n) = logm+logn
We know that loga+logb=logab
So,
log(m+n)=logmn
If loga=logb
Then a=b
So log(m+n)=logmn
m+n=mn
m=mn-n
m=n(n-1)
n=m/m-1
Hope this helped you........................
log(m+n) = logm+logn
We know that loga+logb=logab
So,
log(m+n)=logmn
If loga=logb
Then a=b
So log(m+n)=logmn
m+n=mn
m=mn-n
m=n(n-1)
n=m/m-1
Hope this helped you........................
Answered by
1
Logm+ logn=Log(mn) {Using loga+ logb= logab}
→mn=m+n
→n(m-1)=m
n=m/(m-1) [HENCE PROVED]
→mn=m+n
→n(m-1)=m
n=m/(m-1) [HENCE PROVED]
Similar questions