plzzz help me to do this ques plzzz
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Ashishkumar098:
There is a small mistake
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Ello !!
Here's your answer
____________________
( a + b )^2 x^2 - ( a + b ) x - 6 = 0
= > ( a + b )^2 x^2 - { 3 ( a + b ) - 2 ( a + b ) } x - 6 = 0
[ • Note :- 3 ( a + b ) - 2 ( a + b ) = ( a + b ) ]
= > ( a + b )^2 x^2 - 3 ( a + b ) x + 2 ( a + b ) x - 6 = 0
= > ( a + b ) x { ( a + b ) x - 3 } + 2 { ( a + b ) x - 3 } = 0
= > { ( a + b ) x - 3 } { ( a + b ) x + 2 } = 0
or , { ( a + b ) x - 3 } = 0. Nither , { ( a + b ) x + 2 } = 0
= > ( a + b ) x = 3. = > ( a + b ) x = - 2
= > x = 3 / ( a + b ). = > x = - 2 / ( a + b )
★ So the value of x = 3 / ( a + b ) and - 2 / ( a + b )
__________________________
Hope it helps you!
★ Devil king
Here's your answer
____________________
( a + b )^2 x^2 - ( a + b ) x - 6 = 0
= > ( a + b )^2 x^2 - { 3 ( a + b ) - 2 ( a + b ) } x - 6 = 0
[ • Note :- 3 ( a + b ) - 2 ( a + b ) = ( a + b ) ]
= > ( a + b )^2 x^2 - 3 ( a + b ) x + 2 ( a + b ) x - 6 = 0
= > ( a + b ) x { ( a + b ) x - 3 } + 2 { ( a + b ) x - 3 } = 0
= > { ( a + b ) x - 3 } { ( a + b ) x + 2 } = 0
or , { ( a + b ) x - 3 } = 0. Nither , { ( a + b ) x + 2 } = 0
= > ( a + b ) x = 3. = > ( a + b ) x = - 2
= > x = 3 / ( a + b ). = > x = - 2 / ( a + b )
★ So the value of x = 3 / ( a + b ) and - 2 / ( a + b )
__________________________
Hope it helps you!
★ Devil king
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