Question

plzzz help me to do this ques plzzz

Answer 1

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Answer 2

Ello !!

Here's your answer

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( a + b )^2 x^2 - ( a + b ) x - 6 = 0

= > ( a + b )^2 x^2 - { 3 ( a + b ) - 2 ( a + b ) } x - 6 = 0

[ • Note :- 3 ( a + b ) - 2 ( a + b ) = ( a + b ) ]

= > ( a + b )^2 x^2 - 3 ( a + b ) x + 2 ( a + b ) x - 6 = 0

= > ( a + b ) x { ( a + b ) x - 3 } + 2 { ( a + b ) x - 3 } = 0

= > { ( a + b ) x - 3 } { ( a + b ) x + 2 } = 0

or , { ( a + b ) x - 3 } = 0. Nither , { ( a + b ) x + 2 } = 0

= > ( a + b ) x = 3. = > ( a + b ) x = - 2

= > x = 3 / ( a + b ). = > x = - 2 / ( a + b )


★ So the value of x = 3 / ( a + b ) and - 2 / ( a + b )

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Hope it helps you!

★ Devil king