Question

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Two candles A and B of the same height are lighted at the same instant. A is consumed in 4 hours while B in 3 hours. Assume each candle burns at a constant rate. In how many hours after being lighted was A twice the height of B ?

Answer 1

Answer:

let after x minutes this happened

in this x minutes candle a burned x/240

remaining candle is 1-x/240=240-x/240

and candle b after that x minutes is 180-x/180

now 240-x/240=2*180-x/180

240-x/240=360-2x/180

240-x/4=360-2x/3

720-3x=1440-8x

-5x=-720

x=144minutes

Answer 2

Answer:

Step-by-step explanation:

Here the time taken be ‘x’

Then,

X/4 - (X/2)/3 = 1

{ burning at constant rate so equals 1}

{(x/2) means the height of second candle becomes half}

Then on calculating we get:

X/4 - X/6 = 1

ie, (3X+2X)/12 =1

So,

X= 2.4 hr = 144 minutes.