Question

x:y=3:2,than the ratio (2x² +3y²):(3x²-2y²)=?​

Answer 1

Answer:

$Ratio= \frac{2x^{2}+3y^{2}}{3x^{2}-2y^{2}}\\=\frac{30}{19}$

Step-by-step explanation:

Given x:y = 3:2

Let x = 3m, and y = 2m

$Now, \frac{2x^{2}+3y^{2}}{3x^{2}-2y^{2}}\\=\frac{2(3m)^{2}+3(2m)^{2}}{3(3m)^{2}-2(2m)^{2}}\\=\frac{18m^{2}+12m^{2}}{27m^{2}-8m^{2}}\\=\frac{30m^{2}}{19m^{2}}\\=\frac{30}{19}$

Therefore,

$Ratio= \frac{2x^{2}+3y^{2}}{3x^{2}-2y^{2}}\\=\frac{30}{19}$

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