prove that bisector of any two opposite angles of a parallelogram are parallel .
Answers
Answered by
7
ABCD is parallelogram..............given
DE bisect < D, BF bisect < B..................given
<D = <B....................opposite angles of parallelogram are equal
<1 = <2 ................equal angle bisect still equal
<A = <C ....................opposite angles of parallelogram are equal
AD = BC ......................opposite sides of parallelogram are equal
ΔADE ≅ ΔCBF...................ASA
DE = BF..................CPCTC
DE bisect < D, BF bisect < B..................given
<D = <B....................opposite angles of parallelogram are equal
<1 = <2 ................equal angle bisect still equal
<A = <C ....................opposite angles of parallelogram are equal
AD = BC ......................opposite sides of parallelogram are equal
ΔADE ≅ ΔCBF...................ASA
DE = BF..................CPCTC
Attachments:

cuteboyvishal:
hii
Similar questions