Prove that the distance between a(1,2) and b(3,8) is double the distance of c(3,-1) from the origin.
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V (x2 – r1)2 + (y2 – y1)? Now Distance between A and B – 1)2 + (8 – 2)2 (3 - = v 22+6? = V4+36 = v40 = V4*10=2v10. Distance between C and origin V(3 – 0)? +(-1+ 0)² = v9+1 = v10 Distance between A and B = 2 ( Distance between C and origin) = 2v10 =2 * V10
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