prove that the product of two consecutive positive integers is divisible by 2..
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6
Answer:
- Hence any integer is of one of the form 2q, 2q+1. Hence n(n+1) = 2((2q+1)(q+1)), which is even. Hence n(n+1) is always even. Hence the product of two consecutive integers is always divisible by 2.
- Step-by-step explanation:
Oye
Answered by
1
Answer:
let the two consecutive number be 2 and 3
According to the question
Product = Divisible by 2
Now
2×3= Divisible by 2
6 = Divisible by 2
So it's proved
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