Question

prove that (x^a+b)^2 X (x^b+c)^2 X. (x^c+a)^2 /x^ax^bx^c=1

Answer 1

Sorry but ur question is wrong..........If I will try to solve it the answer is.........

x∧4a+4b+4c ÷ x∧ax+bx+c

or x=(-3)

Be happy............

Answer 2

there seems to be some thing not right in the question.

$(x^{a+b})^2 \times (x^{b+c})^2 \times (x^{c+a})^2\\\\= x^{2a+2b}*x^{2b+2c}*x^{2c+2a}=x^{4a+4b+4c}\\\\LHS=x^{4a+4b+4c-a-b-c}=x^{3a+3b+3c}$