Prove the following: 3sin⁻¹x=sin⁻¹(3x-4x³),x⋲[-1/2,1/2]
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Put x= sin Q
Q = sin inverse x - - - - - - - - 1
The equation becomes,
Sin inverse ( 3sinQ - 4 sin cube Q)
As 3sinQ - 4SincubeQ = Sin3Q then,
Sin inverse(sin3Q) = 3Q = 3sin inverse x(from 1)
Hope you get your answer.☺️
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