Question

Q.11 A solid cuboid of dimnsions 120 cm x 54 cm x 60 cm. How many small cubes with 6 cm can be
cut from given cuboid?
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Answer 1

Step-by-step explanation:

GIVEN :-

$\sf \: Dimension \: of \: cubiod$

$\sf \: length \: (l) \: = 120 \: cm \\ \sf \: breadth \: (b) = 54 \: cm \\ \sf \: height \: (h) = 60 \: cm \: \:$

$\sf \: Side \: of \: small \: cube = 6 \: cm$

TO FIND :-

$\sf \: No. \: of \: cubes \: can \: be \: cut$

SOLUTION :-

$\sf \: Let \: no \: of \: cubes \: be \: n$

• Note volume of cubiod must be equal to the sum of volume of all the cubes.

$\sf \: Volume \: of \: cubiod(V) = (l \times b \times h)$

$\sf \: V = (120 \times 54\times 60) \\ \sf = 388800 \: {cm}^{3} \: \: \:$

$\sf \: Volume \: of \: 1 \: cube = {side}^{3}$

$\sf \: Volume \: of \: 1 \: cube(v) = {6}^{3} \: \: \: \: \: \: \: \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf = 216$

$\sf \: No. \: of \: cubes = \frac{volume \: of \: cubiod}{volume \: of \: 1 \: cube} \\ \\ \sf \: \: \: \: \: \: \: \: = \frac{388800}{216} \\ \\ \sf \: = 1800$

$\sf \: Hence \: no. \: of \: cubes. \: \green{n = 1800}$

• Note Volume of cubiod = (length×breadth×height)
• Volume of cube = (side)^3

Thank you.

Answer 2

Answer:

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Step-by-step explanation:

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