Q. The ratio between the ages of a man and his wife is 4:3. After 4 years, this ratio will be 9:7. If at the time of marriage, the ratio was 5:3, then how many years ago were they married?
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let the age of man presently be x, and of wife is y
so
so 3x=4y
so
after 4 years,
so 7(x+4)=9(y+4)
7x+28=9y+36
so 7x-9y=8
put x=4y/3
we get y=24. thus x=32
at marriage,
let the years of marriage be 'a'
so
thus we get a=12
thus they were married 12 years ago
so
so 3x=4y
so
after 4 years,
so 7(x+4)=9(y+4)
7x+28=9y+36
so 7x-9y=8
put x=4y/3
we get y=24. thus x=32
at marriage,
let the years of marriage be 'a'
so
thus we get a=12
thus they were married 12 years ago
Answered by
2
Given:
- The ratio of the ages of a man and his wife is 4:3
- After 4 years, the ratio will be 9:7
- Time of marriage, the ratio was 5:3
To find:
- Years ago they married?
Solution:
✪ Lets consider the Present age of man and his wife be 4x and 3x respectively.
Then, After 4 years,⠀⠀⠀⠀
- Husband's age = (4x + 4) years
- Wife's age = (3x + 4) years
- After 4 years, The ratio of the age of a man and his wife will be 9:7.⠀⠀⠀⠀⠀
Therefore,
- The Present age of Man, 4x = 4×8 = 32 years
- The Present age of his wife, 3x = 3×8= 24years
✪ Now, Lets assume that their marriage took place in "T years" back.
⠀⠀⠀⠀
Then, By given Condition,
- The ratio of the age of a man and his wife at the time of marriage is 5:3.
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