Q4 ddt question plz solve if the concentration of dtt was 0.2 PPM in water of a lake what would be the concentration in fish if the food chain is plankton fish fish eating Birds
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HEMANTHKUMAR007:
can I know the answer for rectified spirit
Lol ok it is 95 percent ethanol and 5 percent water
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Given,
Concentration of DDT in water =0.2ppm
Therefore, Concentration of DDT in plankton = 0.2 * 10% ( 10% law )
Therefore, Concentration of DDT in fish = 0.2 * 10% * 10%
At last, Concentration of DDT in fish-eating birds = 0.2 * 10% * 10% * 10%
==> 0.0002ppm
Therefore, Concentration of DDT in birds = 0.0002 ppm.
Thank you __/|\__
Concentration of DDT in water =0.2ppm
Therefore, Concentration of DDT in plankton = 0.2 * 10% ( 10% law )
Therefore, Concentration of DDT in fish = 0.2 * 10% * 10%
At last, Concentration of DDT in fish-eating birds = 0.2 * 10% * 10% * 10%
==> 0.0002ppm
Therefore, Concentration of DDT in birds = 0.0002 ppm.
Thank you __/|\__
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The ans is wrong
It will increase not reduce
actuallly I have done a mistakr
u should do by the following
0.2 + 0.2 *10%
it is concentration in plankton
u should add first
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