Math, asked by yashverdhansingh, 8 months ago

Q7. Form a quadratic polynomial whose zeroes are 3 + ✓2 and 3 -✓2.​

Answers

Answered by himansh46
0

Answer:

ehajnababababahbsbzbanba

Answered by aryan073
1

Answer:

<body bgcolor ="lavender "><font color ="blue ">

Step-by-step explanation:

 by \: formation \: of \: quadratic \: equation....

 {x}^{2}  - ( \alpha  +  \beta ) x+  \alpha  \beta  = 0

 \alpha  = 3 +  \sqrt{2}  \:  \:  \:  \:  \:  \beta  = 3 -  \sqrt{2}

 {x}^{2}  - (3 +  \sqrt{2}  + 3 -  \sqrt{2} ) x+ 3(3 +  \sqrt{2} )  -  \sqrt{2} (3 +  \sqrt{2} )

 {x}^{2}  - 6x + 9  + 3 \sqrt{2}  - 3 \sqrt{2 }  - 2

 {x}^{2}  - 6x + 9 - 2 = 0

 {x}^{2}  - 6x + 7 = 0

Similar questions