Question

Question 12.36 In the organic compound CH2=CH–CH2–CH2–C≡CH, the pair of hydridised orbitals involved in the formation of: C2 – C3 bond is:

(a) sp – sp2(b) sp – sp3(c) sp2 – sp3 (d) sp3– sp3

Class XI Organic Chemistry : Some Basic Principles and Techniques Page 364

Answer 1

Hi

Here is your answer,

(c) When double and triple bonds are present at equivalent bonds are present at equivalent positions, then preference is given to double bond while numbering the carbon chain. Thus,
      1         2      3       4        5     6
    CH₂ -- CH - CH₂ - CH₂ - C ≡ CH         (-- double bond)
     sp²     sp²     sp³    sp³     sp   sp

∴ C₂ - C₃ bond if formed by overlap of sp² and sp³ orbitals.


Hope it helps you !

Answer 2

we know, when both double and triple bond are present at equivalent positions then we have to give preference of double bond.
hence, numbering of Carbon chain start near of double bond .
see attachment , here it is clear that which is C2-C3 bond .
hence, C2-C3 bond is formed by overlap of sp² and sp³ orbitals. hence, option (C) is correct.