Question

Question 12.35 In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.

Class XI Organic Chemistry : Some Basic Principles and Techniques Page 364

Answer 1

Hi

Here is your answer,

The mass of organic compound taken = 0.468 g

Mass of BaSo₄ formed = 0.668 g

Percentage of sulphur = 32/233 × mass of BaSO₄ formed/mass of substance taken × 100

 = 32/233 × 0.668/0.468 × 100 = 19.60%


Hope it helps you !

Answer 2

the mass of organic compound taken = 0.468g
mass of BaSO4 formed = 0.668g
we know,
atomic mass of sulphur = 32g/mol
molecular mass of BaSO4 = 233 g/mol

Applying the relation,
Percentage of sulphur = (32/233) × {mass of BaSO4 formed/mass of organic substance taken } × 100

= (32/233) × {0.668/0.468}×100
= 3200× 668/(233 ×468)
= 19.60 %

Hence, percentage of sulphur in the given compound is 19.6%