Question 4 Solve 3x + 8 > 2, when
(i) x is an integer
(ii) x is a real number
Class X1 - Maths -Linear Inequalities Page 122
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3x + 8 > 2
3x + 8 - 8 > 2 - 8 [ subtract 8 both sides]
3x > -6 [ divide by 3 both sides, ]
x > -2 _____________(1)
(i) when x is an integer .
e.g x may be negative or positive .
{ 1, 2, 3, ......0 , .....-3, -2, -1 is known as integer numbers }
from eqn (1)
x > -2 . e.g x will be { -1 , 0, 1 , .....}
(ii) when x is a real number.
and we know, rational and irrational numbers are real numbers.
then x belongs to ( -2, ∞)
3x + 8 - 8 > 2 - 8 [ subtract 8 both sides]
3x > -6 [ divide by 3 both sides, ]
x > -2 _____________(1)
(i) when x is an integer .
e.g x may be negative or positive .
{ 1, 2, 3, ......0 , .....-3, -2, -1 is known as integer numbers }
from eqn (1)
x > -2 . e.g x will be { -1 , 0, 1 , .....}
(ii) when x is a real number.
and we know, rational and irrational numbers are real numbers.
then x belongs to ( -2, ∞)
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