Question 5 A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed. Find the probability that the sum of numbers that turn up is (i) 3 (ii) 12
Class X1 - Maths -Probability Page 404
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number of possible outcomes in coin = 2 { head and tail }
Number of possible outcomes in dice = 6 { there are 6 faces in dice }
∴ total number of possible outcomes n(S) = 2 × 6 = 12
(I) the sum of the numbers that turn up is 3
This is only if 1 turn up on coin and 2 turn up on dice .
Hence, only possible is ( 1, 2)
∴ number of favourable outcomes n(E) = 1
∴ P(E) = n(E)/n(S) = 1/12
(ii) The sum of the number that turn up is 12
This is only if 6 turn up on coin and 6 turn up on dice too .
hence , only possibility is ( 6, 6)
∴ number of favourable outcomes n(E) = 1
∴ P(E) = n(E)/n(S ) = 1/12
Number of possible outcomes in dice = 6 { there are 6 faces in dice }
∴ total number of possible outcomes n(S) = 2 × 6 = 12
(I) the sum of the numbers that turn up is 3
This is only if 1 turn up on coin and 2 turn up on dice .
Hence, only possible is ( 1, 2)
∴ number of favourable outcomes n(E) = 1
∴ P(E) = n(E)/n(S) = 1/12
(ii) The sum of the number that turn up is 12
This is only if 6 turn up on coin and 6 turn up on dice too .
hence , only possibility is ( 6, 6)
∴ number of favourable outcomes n(E) = 1
∴ P(E) = n(E)/n(S ) = 1/12
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