Question

Question 8.29 Given the standard electrode potentials,

K+/K = –2.93V, Ag+/Ag = 0.80V,

Hg2+/Hg = 0.79V

Mg2+/Mg = –2.37V. Cr3+/Cr = –0.74V

Arrange these metals in their increasing order of reducing power.

Class XI Redox Reactions Page 275

Answer 1

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Answer 2

concept :- if on combining an electrode A with the normal Hydrogen electrode , a reduction process { e.g., gain of electrons } occurs at the electrode, the potential of electrode is known as reduction potential. and at 1 atm pressure and 1M concentration of electrolyte , electrode potential is known as standard electrode potential .

smaller the value of standard electrode potential, stronger is the reducing agent and larger the value of standard electrode potential, stronger is the oxidizing agent.


here, we see
decreasing order of standard electrode potential : Ag < Hg < Cr < Mg < K
hence, increasing order of reducing power
Ag < Hg < Cr < Mg < K