Math, asked by meghamulge67, 4 months ago

Question No. 1
The value of
(6.43)? +33.3074 +(5.18)
6.43x41.3449-10.36x 2.59 x 5.18
lies between
0 0.1 and 0.5
O 0.5 and 1
0 1 and 1.2
O 1.2 and 1.5
BA​

Answers

Answered by knjroopa
13

Step-by-step explanation:

Given The value of(6.43)² +33.3074+(5.18)²

____________________

6.43x41.3449-10.36x 2.59x 5.18  lies between ??

  • We need to find the value of the given expression. So we have
  •                            (6.43)^2 + 33.3074 + (5.18)^2 / 6.43 x 41.3449 – 10.36 x 2.59 x 5.18 (using BODMAS application  we have first multiplication and subtraction)
  •                             41.3449 + 33.3074 + 26.8324 / 265.847707 – 138.991832
  •                                 101.4847 / 126.855875
  •                                       = 0.8
  • So 0.8 is in between 0.5 and 1
  • So we have the option 2 as the correct option.

Reference link will be

https://brainly.in/question/21053178

Answered by pulakmath007
46

\displaystyle\huge\red{\underline{\underline{Solution}}}

TO CHOOSE THE CORRECT OPTION

The value of

 \displaystyle \sf{ \frac{ {(6.43)}^{2} + 33.074 +  {(5.18)}^{2}  }{6.43  \times  41.3449 - 10.36  \times  2.59 \times 5.18}  \: }

lies between

 \sf{1. \:  \:  \:  \: 0.1  \:  \: \: and \:   \:  \: \: 0.5 \: }

 \sf{2. \:  \:  \:  \: 0.5  \:  \: \: and \:   \:  \: \: 1 \: }

 \sf{3. \:  \:  \:  \: 1  \:  \: \: and \:   \:  \: \: 1.2 \: }

 \sf{4. \:  \:  \:  \: 1.2  \:  \: \: and \:   \:  \: \: 1.5 \: }

FORMULA TO BE IMPLEMENTED

We are aware of the identity that

 \sf { {a}^{3}  -  {b}^{3}  = (a - b)( {a}^{2} + ab +  {b}^{2})  \: }

CALCULATION

 \displaystyle \sf{ \frac{ {(6.43)}^{2} + 33.074 +  {(5.18)}^{2}  }{6.43 + 41.3449 - 10.36 + 2.59 \times 5.18}  \: }

 =  \displaystyle \sf{ \frac{ {(6.43)}^{2} +( 6.43 \times 5.18) +  {(5.18)}^{2}  }{6.43   \times  6.43 \times 6.43 - (5.18 \times 2  \times  2.59 \times 5.18)} \: }

 =  \displaystyle \sf{ \frac{ {(6.43)}^{2} +( 6.43 \times 5.18) +  {(5.18)}^{2}  }{ {(6.43)}^{3}     - (5.18   \times  5.18 \times 5.18)} \: }

 =  \displaystyle \sf{ \frac{ {(6.43)}^{2} +( 6.43 \times 5.18) +  {(5.18)}^{2}  }{ {(6.43)}^{3}  -  {(5.18)}^{3} } \: }

 =  \displaystyle \sf{ \frac{ {(6.43)}^{2} +( 6.43 \times 5.18) +  {(5.18)}^{2}  }{ {(6.43}  -  {5.18)} \bigg[ \: {(6.43)}^{2} +( 6.43 \times 5.18) +  {(5.18)}^{2} \bigg] } \: }

 =  \displaystyle \sf{ \frac{1 }{ {(6.43}  -  {5.18)}  } \: }

 =  \displaystyle \sf{ \frac{1 }{ 1.25  } \: }

 =  \displaystyle \sf{0.8 }

Hence the value of

 \displaystyle \sf{ \frac{ {(6.43)}^{2} + 33.074 +  {(5.18)}^{2}  }{6.43  \times  41.3449 - 10.36  \times  2.59 \times 5.18}  \: }

 \sf{lies  \: \: between \:  \:  \:  \: 0.5   \: \: and \:   \:   1 \: }

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LEARN MORE FROM BRAINLY

The angles of the triangle are

3x–40, x+20 and 2x–10

then the value of x is

(a) 40 (b) 35 (c) 50 (d) 45

https://brainly.in/question/4194032

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